3. Construct a parallelogram PQRS in which QR = 5.4 cm, SR = 6.0 cm and \angle Q=60{}^\circ . Draw its lines of symmetry, if possible.
3. Construct a parallelogram PQRS in which QR = 5.4 cm, SR = 6.0 cm and \angle Q=60{}^\circ . Draw its lines of symmetry, if possible.

Solution:-

Steps of construction:

1. Draw a line segment QR = 5.4 cm.

2. At Q, draw a ray making an angle of  60{}^\circ with QR

3. Along a ray, set off QP = 6 cm.

4. With P as a center and radius 5.4 cm, draw an arc.

5. With R as a center and radius 6 cm, draw another arc, cutting the previous arc at S.

6. Join PS and RS.

Then, PQRS is the required parallelogram.

7. So, QS and PR intersect each other at O.

Therefore, there is no line of symmetry in parallelogram PQRS.