4. Find the values of k for which the following equations have real and equal roots (iii)

    \[\left( \mathbf{k}\text{ }+\text{ }\mathbf{1} \right){{\mathbf{x}}^{\mathbf{2}}}~\text{ }\mathbf{2}\left( \mathbf{k}\text{ }\text{ }\mathbf{1} \right)\mathbf{x}\text{ }+\text{ }\mathbf{1}\text{ }=\text{ }\mathbf{0}\]

4. Find the values of k for which the following equations have real and equal roots (iii)

    \[\left( \mathbf{k}\text{ }+\text{ }\mathbf{1} \right){{\mathbf{x}}^{\mathbf{2}}}~\text{ }\mathbf{2}\left( \mathbf{k}\text{ }\text{ }\mathbf{1} \right)\mathbf{x}\text{ }+\text{ }\mathbf{1}\text{ }=\text{ }\mathbf{0}\]

Solution:

Given :

    \[\left( k\text{ }+\text{ }1 \right){{x}^{2}}~\text{ }2\left( k\text{ }\text{ }1 \right)x\text{ }+\text{ }1\text{ }=\text{ }0\]

It’s of the form of

    \[a{{x}^{2~}}+\text{ }bx\text{ }+\text{ }c\text{ }=\text{ }0\]

a = (k + 1), b = -2(k - 1), c = 1

For the given quadratic equation to have real roots

    \[D\text{ }=\text{ }{{b}^{2~}}\text{ }4ac\text{ }=\text{ }0\]

    \[D\text{ }=\text{ }{{\left( -2\left( k\text{ }\text{ }1 \right) \right)}^{2}}~\text{ }4\left( 1 \right)\left( k\text{ }+\text{ }1 \right)\text{ }=\text{ }0\]

    \[\Rightarrow 4{{k}^{2}}~\text{ }2k\text{ }+\text{ }1\text{ }\text{ }k\text{ }\text{ }1\text{ }=\text{ }0\]

 (dividing by 4 both sides)

    \[\Rightarrow {{k}^{2}}~\text{ }3k\text{ }=\text{ }0\]

k(k - 3) = 0

k = 0 or k = 3

The value of k can be 0 or 3 to have real and equal roots.