5. Find the equation of the plane passing through the point (1, 4, -2) and parallel to the plane 2x

Home » 5. Find the equation of the plane passing through the point (1, 4, -2) and parallel to the plane 2x – y + 3z + 7 = 0.

5. Find the equation of the plane passing through the point (1, 4, -2) and parallel to the plane 2x – y + 3z + 7 = 0.

5. Find the equation of the plane passing through the point (1, 4, -2) and parallel to the plane 2x – y + 3z + 7 = 0.

Answer:

Any plane parallel to 2x – y + 3z + 7 = 0 is shown as 2x – y + 3z + d = 0.

It passes through the point (1, 4, -2)

$\begin{array}{l} 2 \times 1 - 4 + 3( - 2) + d = 0\\ 2 - 4 - 6 + d = 0\\ d = 8 \end{array}$

The equation of the plane is 2x – y + 3z + 8 = 0.

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