Radius of metallic sphere = 2mm = 1/5 cm
![\[\begin{array}{*{35}{l}} Volume\text{ }=\text{ }4/3\text{ }\pi {{r}^{3}}~=\text{ }4/3\text{ x }22/7\text{ x }1/5\text{ x }1/5\text{ x }1/5\text{ }=\text{ }88/\text{ }\left( 21\text{ x }125 \right)\text{ }c{{m}^{3}} \\ Volume\text{ }of\text{ }8\text{ }spheres\text{ }=\text{ }\left( 88\text{ x }8 \right)/\text{ }\left( 21\text{ x }125 \right)\text{ }=\text{ }704/\text{ }\left( 21\text{ x }125 \right)\text{ }c{{m}^{3}}~\ldots ..\text{ }\left( i \right) \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-a6582c301b85efa63028b0046db8d20d_l3.png "Rendered by QuickLaTeX.com")
Let the radius of new sphere = R
![\[\begin{array}{*{35}{l}} Volume\text{ }=\text{ }4/3\text{ }\pi {{R}^{3}}~=\text{ }4/3\text{ x }22/7\text{ x }{{R}^{3}}~\ldots \ldots \text{ }\left( ii \right) \\ 704/\text{ }\left( 21\text{ x }125 \right)\text{ }=\text{ }4/3\text{ x }22/7\text{ x }{{R}^{3}} \\ 704/\text{ }\left( 21\text{ x }125 \right)\text{ }=\text{ }88/21\text{ x }{{R}^{3}} \\ {{R}^{3}}~=\text{ }\left( 704\text{ x }21 \right)/\text{ }\left( 21\text{ x }125\text{ x }88 \right)\text{ }=\text{ }8/125 \\ R\text{ }=\text{ }2/5\text{ }=\text{ }0.4\text{ }cm\text{ }=\text{ }4\text{ }mm \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-fbef0be83bba43a64f97b282948522ec_l3.png "Rendered by QuickLaTeX.com")
Therefore, the radius of the new sphere is 4 mm.
8 metallic sphere; each of radius 2 mm, are melted and cast into a single sphere. Calculate the radius of the new sphere.
8 metallic sphere; each of radius 2 mm, are melted and cast into a single sphere. Calculate the radius of the new sphere.
and 
, internal resistance 
and 
, connected in parallel. The equivalent emf of the combination is- (A) 
(B) 
(C) 
(D) 
and 
are collinear, prove that 
and 
be three points such that area of a 
is 4 sq units, find the value of 
.
and 
is 35 sq units.
and 
are collinear.
and 
are collinear.
and 
are collinear.
and 