Answer :

According to the question, the radius of the heel, r = d/2​ = 0.005 m

And the mass of the lady (m) = 50 kg

We know that the expression for the Area of the heel can be written as –

A = πr² = π (0.005)²

A = 7.85 × 10^-5 m²

Expression for the Force on the floor due to the heel is given by –

F = mg = 50 × 9.8

F = 490 N

The pressure exerted by the heel on the floor:

We know that the expression of pressure is force divided by the area, so P = F / A​

Upon substituting values, we get –

P = 490 / 7.85 × 10^-5

Therefore, P = 6.24 ×10⁶ Nm ^-2