A bag contains 3 red balls, 4 blue balls and 1 yellow ball, all the balls being identical in shape and size. If a ball is taken out of the bag without looking into it; find the probability that the ball is: (i) yellow (ii) red
A bag contains 3 red balls, 4 blue balls and 1 yellow ball, all the balls being identical in shape and size. If a ball is taken out of the bag without looking into it; find the probability that the ball is: (i) yellow (ii) red

Solution:

The total number of balls in the bag = 3 + 4 + 1 = 8 balls

So, the number of possible outcomes = 8 = n(S)

(i) Event of drawing a yellow ball = {Y}

So, n(E) = 1

Thus, probability of drawing a yellow ball = n(E)/ n(S) = 1/8

(ii) Event of drawing a red ball = {R, R, R}

So, n(E) = 3

Thus, probability of drawing a red ball = n(E)/ n(S) = 3/8