(I) an indivisible number;

(ii) a number lying somewhere in the range of 2 and 6;

(iii) an odd number.

Solution:

Complete potential occasions when a dice is tossed = 6 (1, 2, 3, 4, 5, and 6)

P(E) = (Number of ideal results/Total number of results)

(I) Total number of indivisible numbers = 3 (2, 3 and 5)

P (getting an indivisible number) = 3/6 = ½ = 0.5

(ii) Total numbers lying somewhere in the range of 2 and 6 = (3, 4 and 5)

P (getting a number somewhere in the range of 2 and 6) = 3/6 = ½ = 0.5

(iii) Total number of odd numbers = 3 (1, 3 and 5)

P (getting an odd number) = 3/6 = ½ = 0.5