A body is initially at rest. It undergoes one-dimensional motion with constant acceleration. The power delivered to it at time t is proportional to
(i) t^{\frac{1}{2}}
(ii) t^{\frac{3}{2}}
(iii) t^{2}
(iv) t
A body is initially at rest. It undergoes one-dimensional motion with constant acceleration. The power delivered to it at time t is proportional to
(i) t^{\frac{1}{2}}
(ii) t^{\frac{3}{2}}
(iii) t^{2}
(iv) t

Let the body mass be m

Let the Acceleration be a

According to Newton’s second law of motion, we have,

F=m a( constant )

As, \mathrm{a}=\frac{d v}{d t}= constant

d v=d t \times constant

On integrating we get,

Where, \alpha is a constant

\mathrm{v} \propto \mathrm{t} \rightarrow 2

The relation of power is given by:

From equation 1 \& 2

P \propto t

Thus, we can say that power is proportional to time.