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Home » A body of mass travels in a straight line with velocity where . What is the work done by the net force during its displacement from to m?
A body of mass 0.5 \mathrm{~kg} travels in a straight line with velocity v=\mathrm{ax}^{3 / 2} where \mathrm{a}=5 \mathrm{~m}^{-1 / 2} \mathrm{~s}^{-1}. What is the work done by the net force during its displacement from x=0 to x=2 m?
CBSE | Class 11 | NCERT | Physics | Work, Energy, and Power
A body of mass 0.5 \mathrm{~kg} travels in a straight line with velocity v=\mathrm{ax}^{3 / 2} where \mathrm{a}=5 \mathrm{~m}^{-1 / 2} \mathrm{~s}^{-1}. What is the work done by the net force during its displacement from x=0 to x=2 m?

Let the mass of the body be m

m=0.5 \mathrm{~kg}

Velocity of the body is represented by v=a x^{3 / 2}

where,

a=5 \mathrm{~m}^{-1 / 2} \mathrm{~s}^{-1}.

Initial velocity at x=0 will be v_{1}=a \times 0=0

Final velocity at x=2 will be v_{2}=a(2)^{3 / 2}=5 \times(2)^{3 / 2}

Work done by the system=increase in K.E of the body

=1 / 2 m\left(v_{2}^{2}-v_{1}^{2}\right)=1 / 2 \times 0.5\left[\left(5 \times(2)^{3 / 2}\right)^{2}-0\right]

=(1 / 2) \times 0.5 \times(25 \times 8)=50J

i

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