A box contains 7 red balls, 8 green balls and 5 white balls. A ball is drawn at random from the box. Find the probability that the ball is: (i) white (ii) neither red nor white. - Noon Academy

A box contains 7 red balls, 8 green balls and 5 white balls. A ball is drawn at random from the box. Find the probability that the ball is: (i) white (ii) neither red nor white.

CBSE | Class 10 | Exercise 25C | Maths | Probability | Selina

A box contains 7 red balls, 8 green balls and 5 white balls. A ball is drawn at random from the box. Find the probability that the ball is: (i) white (ii) neither red nor white.

Solution:

We have,

Total number of balls in the box = 7 + 8 + 5 = 20 balls

Total possible outcomes = 20 = n(S)

(i) Event of drawing a white ball = E = number of white balls = 5

So, n(E) = 5

Hence, probability of drawing a white ball = n(E)/ n(S) = 5/20 = 1/4

(ii) Neither red ball nor white ball = green ball

Event of not drawing a red or white ball = E = number of green ball = 8

So, n(E) = 8

Hence, probability of drawing a white ball = n(E)/ n(S) = 8/20 = 2/5

i

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