A capillary tube is dipped in water, the water rises in it to a height ‘h’. If ‘ \mathrm{r} ‘ is the radius of bore of tube then
A. h \alpha r^{2}
B. h \alpha 1 / r
C. h \alpha r
D. h \alpha 1 / r^{2}
A capillary tube is dipped in water, the water rises in it to a height ‘h’. If ‘ \mathrm{r} ‘ is the radius of bore of tube then
A. h \alpha r^{2}
B. h \alpha 1 / r
C. h \alpha r
D. h \alpha 1 / r^{2}

Correct answer is B.

We have,
\mathrm{h}=\frac{2 \sigma \cos \theta}{\mathrm{r} \rho \mathrm{g}}
\Rightarrow \mathrm{h} \cdot \mathrm{r}= constant