Answer : To find: number of 3 digit numbers he can make If all were distinct, he could have made 3! = 6 numbers But 2 number are the same
So the number of possibilities
He can make 3 three – digit numbers using them
Answer : To find: number of 3 digit numbers he can make If all were distinct, he could have made 3! = 6 numbers But 2 number are the same
So the number of possibilities
He can make 3 three – digit numbers using them