A company manufactures scooters at two plants, A and B. plant A produces 80 \% and plant B produces 20 \% of the total product. 85 \% of the scooters produced at pant A and 65 \% of the scooters produced at plant B are of standard quality. A scooter produced by the company is selected at random, and it is found to be of standard quality. What is the probability that it was manufactured at plant A?
A company manufactures scooters at two plants, A and B. plant A produces 80 \% and plant B produces 20 \% of the total product. 85 \% of the scooters produced at pant A and 65 \% of the scooters produced at plant B are of standard quality. A scooter produced by the company is selected at random, and it is found to be of standard quality. What is the probability that it was manufactured at plant A?

Let S : Standard quality
We want to find \mathrm{P}(\mathrm{A} \mid \mathrm{S}), i.e. probability that selected standard scooter is from
plant A
\mathrm{P}(\mathrm{A} \mid \mathrm{S})=\frac{\mathrm{P}(\mathrm{A}) \cdot \mathrm{P}(\mathrm{A} \mid \mathrm{S})}{\mathrm{P}(\mathrm{A}) \cdot \mathrm{P}(\mathrm{S} \mid \mathrm{A})+\mathrm{P}(\mathrm{B}) \cdot \mathrm{P}(\mathrm{S} \mid \mathrm{B})}
Where, \mathrm{P}(\mathrm{A})= probability that scooter is from \mathrm{A}=\frac{80}{100}
P(B)= probability that scooter is from B=\frac{20}{100}
\mathrm{P}(\mathrm{S} \mid \mathrm{A})= probability that standard scooter from \mathrm{A}=\frac{85}{100}
P(S \mid B)= probability that standard scooter from B=\frac{65}{100}
\begin{array}{l} P(A \mid S)=\frac{(80)(85)}{(80)(85)+(20)(65)} \\ =\frac{6800}{6800+1300}=\frac{68}{81} \end{array}
Therefore, the probability of selected standard scooter is from plant A is \frac{68}{81}