Solution:

Given,

Mass of the copper block, m = 2.5 kg

The temperature of the block, ΔT= 500⁰ C

Specific heat of copper, c= 0.39 J g^–1 K^–1

Latent Heat of fusion of water, L = 335 J g^–1

Let m’ be the mass of the ice melted

Heat gains or losses cause temperature, condition, or work changes. Heat is energy transfer. An object’s energy changes when it gains or loses it.

Therefore, heat gained by ice = heat lost by copper

m’L = mcΔT

m’ = mc ΔT/L

m’= (2500 x 0.39 x 500)/335 = 1500 g = 1.5 kg

Thus, value of m’ is 1.5 kg.