A crate contains 12 balls out of which x are dark. On the off chance that one ball is drawn indiscriminately from thebox, what is the likelihood that it will be a debase?On the off chance that 6 more torpedoes are placed in the case, the likelihood of drawing a renounce is presentlytwofold of what it was previously. Discover x
A crate contains 12 balls out of which x are dark. On the off chance that one ball is drawn indiscriminately from thebox, what is the likelihood that it will be a debase?On the off chance that 6 more torpedoes are placed in the case, the likelihood of drawing a renounce is presentlytwofold of what it was previously. Discover x

Solution:

All out number of debases = x

All out number of balls = 12

P(E) = (Number of positive results/Total number of results)

P (getting debases) = x/12 — — — – (I)

Presently, when 6 more debases are added,

Absolute balls become = 18

∴ Total number of renounces = x+6

Presently, P (getting renounces) = (x+6)/18 — — — – (ii)

It’s given that, the likelihood of drawing a renounce now is twofold of what it was previously

(ii) = 2 × (I)

(x+6)/18 = 2 × (x/12)

x + 6 = 3x

2x = 6

∴ x = 3