Solution: Given: I= 1 A, V= 5 V
1) Let R be the resistance of the electric lamp. In series total resistance = 5 + R
I = v/r
1 = 10/5+R
R = 5 ohm
2) V across Lamp + conductor = 10 V
V acoess Lamp = I × R = 1 * 5 = 5 Volt
A current of 1 ampere flows in a series circuit containing an electric lamp and a conductor of 5 Ω when connected to a 10 V battery. Calculate the resistance of the electric lamp. Now if the resistance of 10 Ω is connected in parallel with this series combination, what change (if any) in current flowing through 5 Ω conductor and potential difference across the lamp will take place? Give reason.
A current of 1 ampere flows in a series circuit containing an electric lamp and a conductor of 5 Ω when connected to a 10 V battery. Calculate the resistance of the electric lamp. Now if the resistance of 10 Ω is connected in parallel with this series combination, what change (if any) in current flowing through 5 Ω conductor and potential difference across the lamp will take place? Give reason.