Diameter of cylindrical boiler = 3.5 m
So, the radius (r) = 3.5/2 = 35/20 = 7/4 m
Height (h) = 2m
Radius of hemisphere (R) = 7/4 m
![\[\begin{array}{*{35}{l}} Total\text{ }volume\text{ }of\text{ }the\text{ }boiler\text{ }=\text{ }\pi {{r}^{2}}h\text{ }+\text{ }2/3\text{ }\pi {{r}^{3}} \\ =\text{ }\pi {{r}^{2}}\left( h\text{ }+\text{ }2/3r \right) \\ =\text{ }22/7\text{ x }7/4\text{ x }7/4\text{ }\left( 2\text{ }+\text{ }2/3\text{ x }7/4 \right) \\ =\text{ }77/8\text{ }\left( 2\text{ }+\text{ }7/6 \right) \\ =\text{ }77/8\text{ x }19/6\text{ }=\text{ }1463/48 \\ =\text{ }30.48\text{ }{{m}^{3}} \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-41850ca3e14d90a451997dc8a64ed9aa_l3.png "Rendered by QuickLaTeX.com")
Diameter of cylindrical boiler = 3.5 m
So, the radius (r) = 3.5/2 = 35/20 = 7/4 m
Height (h) = 2m
Radius of hemisphere (R) = 7/4 m
