A cylindrical container with internal radius of its base 10 cm, contains water up to a height of 7 cm. Find the area of wetted surface of the cylinder.

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Class 10 | Cylinder, Cone and Sphere (Surface Area and Volume) | Exercise 20A | ICSE | Selina

A cylindrical container with internal radius of its base 10 cm, contains water up to a height of 7 cm. Find the area of wetted surface of the cylinder.

Internal radius of the cylindrical container = 10 cm = r

Height of water = 7 cm = h

So, the surface area of the wetted surface

$\begin{array}{*{35}{l}} =\text{ }2\pi rh\text{ }+\text{ }\pi {{r}^{2}}~=\text{ }\pi r\left( 2h\text{ }+\text{ }r \right)\text{ }=\text{ }22/7\text{ x }10\text{ x }\left( 2\text{ x }7\text{ }+\text{ }10 \right) \\ =\text{ }220/7\text{ x }24 \\ =\text{ }754.29\text{ }c{{m}^{2}} \\ \end{array}$

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