A dice is thrown once. What is the probability of getting a number: (i) greater than 2? (ii) less than or equal to 2?
A dice is thrown once. What is the probability of getting a number: (i) greater than 2? (ii) less than or equal to 2?

Solution:

The number of possible outcomes when dice is thrown = {1, 2, 3, 4, 5, 6}

So, n(S) = 6

(i) Event of getting a number greater than 2 = E = {3, 4, 5, 6}

So, n(E) = 4

Thus, probability of getting a number greater than 2 = n(E)/ n(S) = 4/6 = 2/3

(ii) Event of getting a number less than or equal to 2 = E = {1, 2}

So, n(E) = 2

Thus, probability of getting a number less than or equal to 2 = n(E)/ n(S) = 2/6 = 1/3