A die is thrown once. Find the probability of getting a number: (i) less than 3 (ii) greater than or equal to 4
A die is thrown once. Find the probability of getting a number: (i) less than 3 (ii) greater than or equal to 4

Solution:

We know that,

In throwing a dice, total possible outcomes = {1, 2, 3, 4, 5, 6}

So, n(S) = 6

(i) On a dice, numbers less than 3 = {1, 2}

So, n(E) = 2

Hence, probability of getting a number less than 3 = n(E)/ n(S) = 2/6 = 1/3

(ii) On a dice, numbers greater than or equal to 4 = {4, 5, 6}

So, n(E) = 3

Hence, probability of getting a number greater than or equal to 4 = n(E)/ n(S) = 3/6 = 1/2