A girl riding a bicycle along a straight road with a speed of 5 m/s throws a stone of mass 0.5 kg which has a speed of 15 m/s with respect to the ground along her direction of motion. The mass of the girl and the bicycle is 50 kg. Does the speed of the bicycle change after the stone is thrown? What is the change in speed, if so?
A girl riding a bicycle along a straight road with a speed of 5 m/s throws a stone of mass 0.5 kg which has a speed of 15 m/s with respect to the ground along her direction of motion. The mass of the girl and the bicycle is 50 kg. Does the speed of the bicycle change after the stone is thrown? What is the change in speed, if so?

Given,

m1 = 50 kg

m2 = 0.5 kg

u1 = 5 m/s

u2 = 5 m/s

v1 = ?

v2 = 15 m/s

The law of conservation of momentum states that

Final momentum equals initial momentum.

u1 = m1v1 + m2v2 (m1 + m2)

We obtain by substituting the values.

v1 = 4.9 m/s v2 = 4.9 m/s v3 = 4.9

As a result, the cycle and the girl’s speed drops by: 5 – 4.9 = 0.1 m/s.