Solution:
(a) Construction: Join BC, and AC then
ABCD is a cyclic quadrilateral.
Now in ∆DCF
Ext. ∠2 = x + z
and in ∆CBE
Ext. ∠1 = x + y
Adding (i) and (ii)
x + y + x + z = ∠1 + ∠2
2 x + y + z = 180o
(ABCD is a cyclic quadrilateral)
But x : y : z = 3 : 4 : 5
x/y = ¾ (y = 4/3 x)
x/z = 3/5 (z = 5/3 x.