The bite the dust is tossed once. What is the likelihood of getting

(I) A?

(ii) D?

Solution:

The complete number of potential results (or occasions) = 6

P(E) = (Number of ideal results/Total number of results)

(I) The complete number of countenances having An on it = 2

P (getting A) = 2/6 = ⅓ = 0.33

(ii) The complete number of countenances having D on it = 1

P (getting D) = ⅙ = 0.166