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Home » A particle moves along a circle of radius ‘r’ with constant tangential acceleration. If the velocity of the particle is ‘ ‘ at the end of second revolution, after the revolution has started then the tangential acceleration isA) B) C) D)
A particle moves along a circle of radius ‘r’ with constant tangential acceleration. If the velocity of the particle is ‘ v ‘ at the end of second revolution, after the revolution has started then the tangential acceleration is
A) \frac{v^{2}}{8 \pi r}
B) \frac{v^{2}}{6 \pi r}
C) \frac{v^{2}}{4 \pi r}
D) \frac{v^{2}}{2 \pi r}
Physics
A particle moves along a circle of radius ‘r’ with constant tangential acceleration. If the velocity of the particle is ‘ v ‘ at the end of second revolution, after the revolution has started then the tangential acceleration is
A) \frac{v^{2}}{8 \pi r}
B) \frac{v^{2}}{6 \pi r}
C) \frac{v^{2}}{4 \pi r}
D) \frac{v^{2}}{2 \pi r}

Answer is (A)
Using v^{2}-u^{2}=2 a s and u=u_{1} and s=4 \pi r
\therefore \quad 2 \mathrm{as}=\mathrm{v}^{2} \Rightarrow \frac{\mathrm{v}^{2}}{2 \mathrm{~s}}=\mathrm{a}=\frac{\mathrm{v}^{2}}{2 \times 4 \pi \mathrm{r}}=\frac{\mathrm{v}^{2}}{8 \pi \mathrm{r}}

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