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Home » A passenger arriving in a new town wants to go from the station to a hotel located 10 km away on a straight road from the station. A dishonest cabman takes him along a circuitous path 23 km long and reaches the hotel in 28 min. (a) What is the average speed of the taxi? (b) What is the magnitude of average velocity? Are the two equal?
A passenger arriving in a new town wants to go from the station to a hotel located 10 km away on a straight road from the station. A dishonest cabman takes him along a circuitous path 23 km long and reaches the hotel in 28 min. (a) What is the average speed of the taxi? (b) What is the magnitude of average velocity? Are the two equal?
CBSE | Class 11 | Motion in a Plane | NCERT | Physics
A passenger arriving in a new town wants to go from the station to a hotel located 10 km away on a straight road from the station. A dishonest cabman takes him along a circuitous path 23 km long and reaches the hotel in 28 min. (a) What is the average speed of the taxi? (b) What is the magnitude of average velocity? Are the two equal?

Answer :

(a) According to the question, the total distance travelled is 23 km and the total time taken is 28 minutes.

Time Taken (in hours) = 28/60 h

Average speed is given as follows :

Average Speed = Total distance / time taken = 23 / (28/60)

Average Speed = 49.29 km/h

(b) According to the question, the distance between the hotel and the station is 10 km, which is equal to the displacement of the car. Therefore,

Average velocity = 10 / (28/60)

Avg. Velocity = 21.43 km/h

Average speed and velocity are not equal to each other.

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