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Home » A pebble of mass 0.05 kg is thrown vertically upwards. Give the direction and magnitude of the net force on the pebble, (a) during its upward motion (b) during its downward motion (c) at the highest point where it is momentarily at rest. Do your Solutions change if the pebble was thrown at an angle of 45° with the horizontal direction? Ignore air resistance
A pebble of mass 0.05 kg is thrown vertically upwards. Give the direction and magnitude of the net force on the pebble, (a) during its upward motion (b) during its downward motion (c) at the highest point where it is momentarily at rest. Do your Solutions change if the pebble was thrown at an angle of 45° with the horizontal direction? Ignore air resistance
CBSE | Class 11 | Laws of Motion | NCERT | Physics
A pebble of mass 0.05 kg is thrown vertically upwards. Give the direction and magnitude of the net force on the pebble, (a) during its upward motion (b) during its downward motion (c) at the highest point where it is momentarily at rest. Do your Solutions change if the pebble was thrown at an angle of 45° with the horizontal direction? Ignore air resistance

(a) The acceleration due to gravity acts downwards throughout the upward motion of the pebble, thus the magnitude of the force on the pebble is

0.5 N = F = mg = 0.05 kg x 10 ms-2

The force is in a downward direction.

(b) The magnitude of the force will be equal to 0.5 N during the downward motion, and the force will act downwards.

(c) The pebble’s velocity will have both horizontal and vertical components if it is thrown at a 45° angle to the horizontal direction. The vertical component of velocity will be 0 at its greatest point, while the horizontal component will remain constant throughout the pebble’s journey. The force applied will be unaffected by this component.

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