A person normally weighing 50 kg stands on a massless platform which oscillates up and down harmonically at a frequency of 2 s-1 and an amplitude 5 cm. A weighing machine on the platform gives the persons weight against time.
A person normally weighing 50 kg stands on a massless platform which oscillates up and down harmonically at a frequency of 2 s-1 and an amplitude 5 cm. A weighing machine on the platform gives the persons weight against time.

a) will there be any change in weight of the body, during the oscillation?

b) if the answer to part a) is yes, what will be the maximum and minimum reading in the machine and at which position?

Answer:

(a) According to the question, frequency  

We know that,
Also, the amplitude is 

The body’s usual reactor will be measured as weight by the weighting equipment.

Now, consider to be the acceleration, then we can write:

 a=A{{\omega }^{2}}=5\times \left( \frac{1}{100} \right)\times {{\left( 4\pi  \right)}^{^{2}}}

a=7.89m/{{s}^{2}}

Now, referring to the image above and balancing the force
Now 
  ……..(1)
As a result, the machine’s weight will be smaller than the real weight.
or (2)
Which shows the weight measured by the machine will be greater than the actual.
So, the answer is “Yes”
(b) Upon putting the known values, we get that the maximum weight is 885 N while the minimum weight is 95.5 N.