The proton and α-particle are accelerated at the same potential difference.
λ = h/√2mqv
λ is proportional to 1/√mq
λp/ λa = √maqa/mpqp = √8
Hence, proton wavelength is √8 times α-particle. wavelength
A proton and an α-particle are accelerated, using the same potential difference. How are the de Broglie wavelengths λp and λa related to each other?
A proton and an α-particle are accelerated, using the same potential difference. How are the de Broglie wavelengths λp and λa related to each other?