Answer:

Given,

The river’s velocity, vr, is 3 meters per second.

vs = 4 m/s is the speed of the swimmer.

a) When the swimmer swims due north, the y-component will have a velocity of 4 meters per second and the x-component will have a velocity of 3 meters per second. As a function of tan, the following is the resultant velocity.

Here, θ = 37^{o}N

b)

If the swimmer intends to reach the place that is exactly opposite him and that is with regard to tan, the following is the consequent speed of the swimmer.

$v=\sqrt{{v}_{s}^{2}\u2013{v}_{r}^{2}}=\sqrt{(4{)}^{2}\u2013(3{)}^{2}}=\sqrt{7}m/s$So, of north