A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is : (1) 0.5 mm (2) 1.0 mm (3) 0.01 mm (4) 0.25 mm
A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is : (1) 0.5 mm (2) 1.0 mm (3) 0.01 mm (4) 0.25 mm

Correct option: 1)

As we know that, Least Count =\frac{\text { Pitch }}{\text { no. of division on circular scale }}

Thus evaluating according to given information, =0.01=\frac{\text { pitch }}{50}
Pitch =0.01 \times 50=0.5 mm