A shot in the dark comprises of turning a bolt which stops pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see Fig. 15.5), and these are similarly probable results. What is the likelihood that it will point at
A shot in the dark comprises of turning a bolt which stops pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see Fig. 15.5), and these are similarly probable results. What is the likelihood that it will point at

(I) 8?

(ii) an odd number?

(iii) a number more noteworthy than 2?

(iv) a number under 9?

Ncert solutions class 10 chapter 15-2

Solution:

Complete number of potential results = 8

P(E) = (Number of great results/Total number of results)

(I) Total number of great occasions (for example 8) = 1

∴ P (pointing at 8) = ⅛ = 0.125

(ii) Total number of odd numbers = 4 (1, 3, 5 and 7)

P (pointing at an odd number) = 4/8 = ½ = 0.5

(iii) Total numbers more noteworthy than 2 = 6 (3, 4, 5, 6, 7 and 8)

P (pointing at a number more noteworthy than 4) = 6/8 = ¾ = 0.75

(iv) Total numbers under 9 = 8 (1, 2, 3, 4, 5, 6, 7, and 8)

P (pointing at a number under 9) = 8/8 = 1