A small signal voltage V(t)=V_{0} \sin \omega t is applied across an ideal capacitor C:
A Current I (\mathrm{t}), lags voltage \mathrm{V}(\mathrm{t}) by 90^{\circ}
B Over a full cycle the capacitor \mathrm{C} does not consume any energy from the voltage source.
C Current I (t) is in phase with voltage V (t).
D \quad Current I (\mathrm{t}) leads voltage \mathrm{V}(\mathrm{t}) by 180^{\circ}.
A small signal voltage V(t)=V_{0} \sin \omega t is applied across an ideal capacitor C:
A Current I (\mathrm{t}), lags voltage \mathrm{V}(\mathrm{t}) by 90^{\circ}
B Over a full cycle the capacitor \mathrm{C} does not consume any energy from the voltage source.
C Current I (t) is in phase with voltage V (t).
D \quad Current I (\mathrm{t}) leads voltage \mathrm{V}(\mathrm{t}) by 180^{\circ}.

Correct Option B

Solution:
In AC circit the power is given by formula,

P=V I \operatorname{Cos} \phi

Because the phase difference in a purely capacitive circuit is 90 degrees, no power is consumed.