A sphere encloses an electric dipole with charges \pm 3 \times 10^{-6} C. What is the total electric flux across the sphere? (1) 6 \times 10^{-6} \mathrm{Nm}^{2} / \mathrm{C} (2) -3 \times 10^{-6} \mathrm{Nm}^{2} / \mathrm{C} (3) Zero (4) 3 \times 10^{-6} \mathrm{Nm}^{2} / \mathrm{C}
A sphere encloses an electric dipole with charges \pm 3 \times 10^{-6} C. What is the total electric flux across the sphere? (1) 6 \times 10^{-6} \mathrm{Nm}^{2} / \mathrm{C} (2) -3 \times 10^{-6} \mathrm{Nm}^{2} / \mathrm{C} (3) Zero (4) 3 \times 10^{-6} \mathrm{Nm}^{2} / \mathrm{C}

Answer (3)
Sol. \phi_{\text {Total }}=\frac{\mathbf{q}_{\text {enclosed }}}{\varepsilon_{0}}

Because dipoles have equal and opposing charges, there will be no net charge inside the sphere.

\left(q_{\text {enolosed }}=0\right)
\begin{aligned} \phi_{\text {Total }} &=\frac{0}{\varepsilon_{0}} \\ &=0 \end{aligned}