Solution:

(I) Number of damaged bulbs = 4

The absolute number of bulbs = 20

P(E) = (Number of great results/Total number of results)

∴ Probability of getting a damaged bulb = P (deficient bulb) = 4/20 = ⅕ = 0.2

(ii) Since 1 non-damaged bulb is drawn, then, at that point the absolute quantities of bulbs left are 19

Along these lines, the absolute number of occasions (or results) = 19

Number of non-damaged bulbs = 19-4 = 15

Along these lines, the likelihood that the bulb isn’t deficient = 15/19 = 0.789