Diameter of the base = 3.5 m
So, its radius = 3.5/2 m = 1.75 m = 7/4 m
Height of cylindrical part = 4 + 2/3 = 14/3
(i)
![\[\begin{array}{*{35}{l}} Capacity\text{ }\left( volume \right)\text{ }of\text{ }the\text{ }vessel\text{ }=\text{ }\pi {{r}^{2}}h\text{ }+\text{ }2/3\text{ }\pi {{r}^{2}}~=\text{ }\pi {{r}^{2~}}\left( h\text{ }+\text{ }2/3r \right) \\ =\text{ }22/7\text{ x }7/4\text{ x }7/4\left( 14/3\text{ }+\text{ }2/3\text{ x }7/4 \right) \\ =\text{ }77/8\left( 14/3\text{ }+\text{ }7/6 \right) \\ =\text{ }77/8\left( 28+7/6 \right) \\ =\text{ }77/8\text{ }x\text{ }35/6 \\ =\text{ }2695/48 \\ =\text{ }56.15\text{ }{{m}^{3}} \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-756e135a5b226b5f287a00a7dd55aa80_l3.png "Rendered by QuickLaTeX.com")
(ii)
![\[\begin{array}{*{35}{l}} Internal\text{ }curved\text{ }surface\text{ }area\text{ }=\text{ }2\pi rh\text{ }+\text{ }2\pi {{r}^{2}}~=\text{ }2\pi r\left( h\text{ }+\text{ }r \right) \\ =\text{ }2\text{ x }22/7\text{ x }7/4\left( 14/3\text{ }+\text{ }7/4 \right) \\ =\text{ }11\left( 56\text{ }+\text{ }21 \right)/12 \\ =\text{ }11\text{ x }77/12 \\ =\text{ }847/12 \\ =\text{ }70.58\text{ }{{m}^{2}} \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-e4ef174924e0ab9ff1471b61232ddc21_l3.png "Rendered by QuickLaTeX.com")
Diameter of the base = 3.5 m
So, its radius = 3.5/2 m = 1.75 m = 7/4 m
Height of cylindrical part = 4 + 2/3 = 14/3
(i)
(ii)
