A vessel of volume V contains a mixture of 1 mole of hydrogen and 1 mole of oxygen. Let f1(v)dv, denote the fraction of molecules with speed between v and (v + dv) with f2(v)dv similarly for oxygen. Then
A vessel of volume V contains a mixture of 1 mole of hydrogen and 1 mole of oxygen. Let f1(v)dv, denote the fraction of molecules with speed between v and (v + dv) with f2(v)dv similarly for oxygen. Then

a) f1(v) + f2(v) = f(v) obeys the Maxwell’s distribution law

b) f1(v), f2(v) will obey the Maxwell’s distribution law separately

c) neither f1(v) nor f2(v) will obey the Maxwell’s distribution law

d) f2(v) and f1(v) will be the same

Answer:

The correct option is b) f1(v), f2(v) will obey Maxwell’s distribution law separately.

Explanation: The average kinetic energy in a combination is equal. As a result, the velocity distribution is significantly different. The mass of the gas molecule affects the Maxwell-Boltzmann speed distribution function. [dN denotes the number of molecules with speeds ranging from v to (v+dv)]. Hydrogen and oxygen molecules have differing masses.