Solution:
![\[\left( iii \right)\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-51bb833668e48c13fb2f3cac010c41f1_l3.png "Rendered by QuickLaTeX.com")
Number of black cards left
![\[=\text{ }23\text{ }cards\text{ }\left( 13\text{ }club\text{ }+\text{ }10\text{ }spade \right)\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-0a21042ed213cb772da1c3fb2c786936_l3.png "Rendered by QuickLaTeX.com")
Event of drawing a black card
![\[=\text{ }E\text{ }=\text{ }23\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-68b2d9079d44f938aa44a6f6bc226f43_l3.png "Rendered by QuickLaTeX.com")
So,
![\[n\left( E \right)\text{ }=\text{ }23\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-004e81df4bd8f73e272cfca3be26c892_l3.png "Rendered by QuickLaTeX.com")
Hence, probability of drawing a black card
![\[=\text{ }n\left( E \right)/\text{ }n\left( S \right)\text{ }=\text{ }23/49\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-2c17278d23a6dda69828e127285d0166_l3.png "Rendered by QuickLaTeX.com")
All the three face cards of spades are removed from a well shuffled pack of
![\[\mathbf{52}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-d3c2ee289e803b11d76d5473900dfaff_l3.png "Rendered by QuickLaTeX.com")
![\[\left( \mathbf{iii} \right)\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-512b94d74fc4a9de10e783f6743c6b28_l3.png "Rendered by QuickLaTeX.com")
All the three face cards of spades are removed from a well shuffled pack of