An aeroplane travelled a distance of 400 km at an average speed of x km/hr. On the return journey, the speed was increased by 40 km/hr. Write down an expression for the time taken for: (i) the onward journey; (ii) the return journey. If the return journey took 30 minutes less than the onward journey, write down an equation in x and find its value.
An aeroplane travelled a distance of 400 km at an average speed of x km/hr. On the return journey, the speed was increased by 40 km/hr. Write down an expression for the time taken for: (i) the onward journey; (ii) the return journey. If the return journey took 30 minutes less than the onward journey, write down an equation in x and find its value.

According to ques,

Distance

    \[=\text{ }400\text{ }km\]

Average speed of the airplane

    \[=\text{ }x\text{ }km/hr\]

Also,

speed while returning

    \[=\text{ }\left( x\text{ }+\text{ }40 \right)\text{ }km/hr\]

Now,

Time = Distance/ Speed

  • Time taken for onward journey

    \[=\text{ }400/x\text{ }hrs\]

  • Time take for return journey

 

Concise Selina Solutions Class 10 Maths Chapter 6 ex. 6(E) - 4

    \[=\text{ }400/\left( x\text{ }+\text{ }40 \right)\text{ }hrs\]

hence,

    \[{{x}^{2}}~+\text{ }40x\text{ }\text{ }32000\text{ }=\text{ }0\]

or,

    \[{{x}^{2}}~+\text{ }200x\text{ }\text{ }160x\text{ }\text{ }32000\text{ }=\text{ }0\]

or,

    \[x\left( x\text{ }+\text{ }200 \right)\text{ }\text{ }160\left( x\text{ }+\text{ }200 \right)\text{ }=\text{ }0\]

or,

    \[\left( x\text{ }+\text{ }200 \right)\text{ }\left( x\text{ }\text{ }160 \right)\text{ }=\text{ }0\]

or,

So,

    \[x\text{ }=\text{ }-200\text{ }or\text{ }160\]

Since the speed cannot be negative,

    \[x\text{ }=\text{ }160\]

is only valid.