Login/Sign Up
Home » An arbitrary surface encloses a dipole. What is the electric flux through this surface?
An arbitrary surface encloses a dipole. What is the electric flux through this surface?
CBSE | Class 10 | Class 12 | Electric Charges and Fields | Physics
An arbitrary surface encloses a dipole. What is the electric flux through this surface?

According to Gauss law, for an enclosed surface, the electric flux is given as:

\oint_{s} \underset{E} \cdot d \frac{q_{e n c l o s e d}}{\epsilon_{0}}

The net charge on the dipole is given as -q and +q whose sum is equal to zero.

i

More Material