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Home » Assign the position of the element having outer electronic configuration (i) for (ii) (n1) for , and (iii) for , in the periodic table.
Assign the position of the element having outer electronic configuration (i) ns ^{2} np ^{4} for n =3 (ii) (n1) d ^{2} ns ^{2} for n =4, and (iii) ( n -2) f ^{7}( n -1) d ^{1} ns ^{2} for n =6, in the periodic table.
CBSE | Chemistry | Class 11 | Classification of Elements and Periodicity in Properties | NCERT
Assign the position of the element having outer electronic configuration (i) ns ^{2} np ^{4} for n =3 (ii) (n1) d ^{2} ns ^{2} for n =4, and (iii) ( n -2) f ^{7}( n -1) d ^{1} ns ^{2} for n =6, in the periodic table.

Answer:

i) Since n = 6, the element is in period 6. f-block element because the last electron enters f-orbital. They are in the third group. So, 54 + 7 + 2 + 1 Equals 64. So Gadolinium is required.

(ii) Since n = 3, the element is in period 3. P-block element because final electron enters p-orbital. It has 4 p-orbital electrons.

For an element group,

= No. of s + d + p block groupings

=2+10+4 = 16

It belongs to the third period and sixteenth group of the periodic table. So Sulphur is required.

iii) So the element is in the fourth period. The element is in the d-block because the last electron enters the d-orbital, which is not fully filled. It has 2 d-orbital electrons.

For an element group, = No. of s + No. of d block groupings= 2+2 = 4

It is in the fourth period and group of the periodic table. So Titanium is necessary.

i

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