Solution:

To start with, compute the space of the square shape and the space of the circle. Here, the space of the square shape is the conceivable result and the space of the circle will be the positive result.

In this way, the space of the square shape = (3×2) m2 = 6 m2

furthermore,

The space of the circle = πr2 = π(½)2 m2 = π/4 m2 = 0.78

∴ The likelihood that kick the bucket will land inside the circle = [(π/4)/6] = π/24 or, 0.78/6 = 0.13