Solution:
At the point when Cr2O72–is treated with an antacid:
![\[\left( orange \right)\text{ }Cr2O72+\text{ }OH-\to \text{ }2CrO42-\left( yellow \right)\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-b0547a5db106eb4d57103626f9fbb3a7_l3.png "Rendered by QuickLaTeX.com")
At the point when the yellow arrangement is treated with a corrosive, we get back the orange arrangement:
![\[\left( yellow \right)2CrO42-+2H+\to Cr2O72\left( orange \right)+\text{ }H2O~\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-db9178872fd3a0d0f719f8458d330db8_l3.png "Rendered by QuickLaTeX.com")
At the point when an orange arrangement containing Cr2O72–particle is treated with an antacid, a yellow arrangement is framed and when H+ particles are added to a yellow arrangement, an orange arrangement is acquired. Clarify for what reason does this occur?
At the point when an orange arrangement containing Cr2O72–particle is treated with an antacid, a yellow arrangement is framed and when H+ particles are added to a yellow arrangement, an orange arrangement is acquired. Clarify for what reason does this occur?