Solution:

We arrange given data in ascending order 1, 2, 3, 3, 3, 4, 5, 5, 6, 7

Mean = Ʃx_i/n

= (1+2+3+3+3+4+5+5+6+7)/10

= 39/10

= 3.9

Here number of observations, n = 10 which is even.

So median = ½ ( n/2 ^th term + ((n/2)+1)^th term)

= ½ (10/2 ^th term + ((10/2)+1)^th term)

= ½ (5 ^th term + (5+1)^th term)

= ½ (5 ^th term + 6^th term)

= ½ (3+4)

= ½ ×7

= 3.5

Hence the median is 3.5.

In the given set, 3 occurs maximum number of times.

Hence the mode is 3.