Solution: Option (C) 10 is the correct answer. The formula for distance: ${{d}^{2}}~=\text{ }{{({{x}_{2}}~\text{ }{{x}_{1}})}^{2}}~+\text{ }{{({{y}_{2}}~\text{ }{{y}_{1}})}^{2}}$ According to the...

Solution: Option (C) 8 is the correct answer. The vertices of the triangle are, $A\text{ }({{x}_{1}},\text{ }{{y}_{1}})=\left( 3,\text{ }0 \right)$ $B\text{ }({{x}_{2}},\text{ }{{y}_{2}})=\left(...

Solution: Option (B) 12 is the correct answer. (0, 4), (0, 0) and (3, 0) are the vertices of a triangle. The perimeter of triangle AOB = Sum of the length of all its sides: = distance between...

Solution: Option (C) √34 is the correct answer. The three vertices are: $A\text{ }=\text{ }\left( 0,\text{ }3 \right)$, $O\text{ }=\text{ }\left( 0,\text{ }0 \right)$ , $B\text{ }=\text{ }\left(...

Solution: Option (B) 5√ 2 is the correct answer. Distance formula: ${{d}^{2}}~=\text{ }{{({{x}_{2}}~\text{ }{{x}_{1}})}^{2}}~+\text{ }{{({{y}_{2}}~\text{ }{{y}_{1}})}^{2}}$ According to the given...

Solution: Option (B) 8 is the correct answer. The formula for distance : ${{d}^{2}}~=\text{ }{{({{x}_{2}}~\text{ }{{x}_{1}})}^{2}}~+\text{ }{{({{y}_{2}}~\text{ }{{y}_{1}})}^{2}}$ According to the...

Solution: Option (B) 3 is the correct answer. We all know that, On the Cartesian plane (x, y) is a point in first quadrant. Then, Perpendicular distance from Y–axis = x, and Perpendicular distance...