Given: tan θ+ sec θ = l … eq. 1 Duplicating and isolating by (sec θ – tan θ) on numerator and denominator of L.H.S, Along these lines, sec θ – tan θ = 1 … eq.2 Adding eq. 1and eq. 2, we get \[\left(...

Considering that an upward banner staff of stature h is overcomed on an upward pinnacle of tallness H(say), with the end goal that FP = h and FO = H. The point of height of the base and top of the...

Considering that an upward banner staff of stature h is overcomed on an upward pinnacle of tallness H(say), with the end goal that FP = h and FO = H. The point of height of the base and top of the...

Let SQ = h be the pinnacle. ∠SPQ = 30° and ∠SRQ = 60° As per the inquiry, the length of shadow is 50 m long hen point of rise of the sun is 30° than when it was 60°. Thus, PR = 50 m and RQ = x m So...

Allow Zeba's to age = x As indicated by the inquiry, \[\left( x-5 \right){}^\text{2}=11+5x\] \[x{}^\text{2}+25-10x=11+5x\] \[x{}^\text{2}-15x+14=0\] \[x{}^\text{2}-14x-x+14=0\] \[x\left( x-14...

Let unique speed of train = x km/h We know, Time = distance/speed As indicated by the inquiry, we have, Time taken via train = 360/x hour What's more, Time taken via train its speed increment 5 km/h...

Let the normal number = 'x'. As per the inquiry, We get the condition, \[x{}^\text{2}\text{ }\text{ }84\text{ }=\text{ }3\left( x+8 \right)\] \[x{}^\text{2}\text{ }\text{ }84\text{ }=\text{...