Exercise 15.1

12 flawed pens are inadvertently blended in with 132 great ones. It is unimaginable to simply take a gander at a pen and tell whether it is blemished. One pen is taken out aimlessly from this parcel. Decide the likelihood that the pen taken out is a decent one.

Solution: Quantities of pens = Numbers of blemished pens + Numbers of good pens ∴ Total number of pens = 132+12 = 144 pens P(E) = (Number of great results/Total number of results) P(picking a decent...

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(I) A ton of 20 bulbs contain 4 blemished ones. One bulb is drawn indiscriminately from the part. What is the likelihood that this bulb is damaged?(ii) Suppose the bulb attracted (I) isn’t damaged and isn’t supplanted. Presently one bulb is drawn indiscriminately from the rest. What is the likelihood that this bulb isn’t deficient?

Solution: (I) Number of damaged bulbs = 4 The absolute number of bulbs = 20 P(E) = (Number of great results/Total number of results) ∴ Probability of getting a damaged bulb = P (deficient bulb) =...

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A great deal comprises of 144 ball pens of which 20 are deficient and the others are acceptable. Nuri will purchase a pen in case it is acceptable, yet won’t accepting in case it is damaged. The retailer draws one pen indiscriminately and offers it to her. What is the likelihood that

(I) She will get it? (ii) She won't get it? Arrangement: The all out quantities of results for example pens = 144 Given, quantities of inadequate pens = 20 ∴ The quantities of non inadequate pens =...

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(I) Complete the accompanying table: (ii) An understudy contends that ‘there are 11 potential results 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. In this way, every one of them has a likelihood 1/11. Do you concur with this contention? Legitimize your Solution:.

Solution: On the off chance that 2 dices are tossed, the potential occasions are: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3,...

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A game comprises of throwing a one rupee coin multiple times and taking note of its result each time. Hanif wins if every one of the throws give a similar outcome i.e., three heads or three tails, and loses in any case. Ascertain the likelihood that Hanif will lose the game.

Solution: The absolute number of results = 8 (HHH, HHT, HTH, THH, TTH, HTT, THT, TTT) Absolute results in which Hanif will lose the game = 6 (HHT, HTH, THH, TTH, HTT, THT) P (losing the game) = 6/8...

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