Solution: If $b>0, \sqrt{a+i b}=\pm\left[\left(\frac{a+\sqrt{a^{2}+b^{2}}}{2}\right)^{\frac{1}{2}}+i\left(\frac{-a+\sqrt{a^{2}+b^{2}}}{2}\right)^{\frac{1}{2}}\right]$ If $b<0, \sqrt{a+i...
Solution: If $b>0, \sqrt{a+i b}=\pm\left[\left(\frac{a+\sqrt{a^{2}+b^{2}}}{2}\right)^{\frac{1}{2}}+i\left(\frac{-a+\sqrt{a^{2}+b^{2}}}{2}\right)^{\frac{1}{2}}\right]$ If $b<0, \sqrt{a+i...
Solution: If $b>0, \sqrt{a+i b}=\pm\left[\left(\frac{a+\sqrt{a^{2}+b^{2}}}{2}\right)^{\frac{1}{2}}+i\left(\frac{-a+\sqrt{a^{2}+b^{2}}}{2}\right)^{\frac{1}{2}}\right]$ If $b<0, \sqrt{a+i...
Solution: If $b>0, \sqrt{a+i b}=\pm\left[\left(\frac{a+\sqrt{a^{2}+b^{2}}}{2}\right)^{\frac{1}{2}}+i\left(\frac{-a+\sqrt{a^{2}+b^{2}}}{2}\right)^{\frac{1}{2}}\right]$ If $b<0, \sqrt{a+i...
Think about the accompanying graph Volume of water that streams in t minutes from pipe \[=\text{ }t\times 0.5\pi \text{ }m^3\] Volume of water that streams in t minutes from pipe = \[t\times 0.5\pi...
It is given that the waterway is the state of a cuboid with measurements as: Broadness (b) = 6 m and Height (h) = 1.5 m It is additionally given that The speed of waterway = 10 km/hr Length of...
The outline will be as- Given, Tallness $(h_1)$ of tube shaped piece of the pail = 32 cm Range $(r_1)$ of roundabout finish of the pail = 18 cm Tallness of the cone like pile $(h_2)$ = 24 cm...
It is realized that the coins are round and hollow fit. Along these lines, tallness (h1) of the chamber = 2 mm = 0.2 cm Range (r) of roundabout finish of coins \[=\text{...
Number of cones will be = Volume of chamber/Volume of frozen treat For the chamber part, Range = 12/2 = 6 cm Stature = 15 cm ∴ Volume of chamber \[=\text{ }\mathbf{\pi }\times \mathbf{r2}\times...
The state of the well will be tube shaped as given underneath. Given, Depth $(h_1)$ of well = 14 m Distance across of the roundabout finish of the well =3 m Thus, Radius $(r_1)$ = 3/2 m Width of the...
t is given that the state of the well is looking like a chamber with a width of 7 m In this way, span = 7/2 m Likewise, Depth (h) = 20 m Volume of the earth uncovered will be equivalent to the...
For Sphere 1: Span (r1) = 6 cm ∴ Volume (V1) \[=\text{ }\left( 4/3 \right)\times \pi \times r13\] For Sphere 2: Span (r2) = 8 cm ∴ Volume (V2) \[=\text{ }\left( 4/3 \right)\times \pi \times r23\]...
It is given that range of the circle (R) = 4.2 cm Likewise, Radius of chamber (r) = 6 cm Presently, let stature of chamber = h It is given that the circle is liquefied into a chamber. Along these...