Solution:- Calculate  Mean for Length x,

Solution:- According to the  given data, Draw  the table of the given data and append other columns after calculations. Since C.V. of firm B is greater Therefore,  Team A is more consistent....

Solution:- (i) According to the  given table, Mean monthly wages of firm A = Rs \[5253\] and Number of wage earners = \[586\] Then, Total amount paid = \[586\text{ }\times \text{ }5253\] = Rs...

    Solution:- From the given data, draw the table of the given data and append other columns after calculations. Now calculate Mean for x, Mean $\bar{X}=\sum {{x}_{i}}/n$ Where, n =...

Solution:- Calculate the coefficient of variance for each series for comparing the variability or dispersion of two series. The series having greater C.V. is said to be more variable than the other....

Calculate the standard deviation and mean diameter of the circles. [Hint first make the data continuous by making the classes as \[32.5-36.5,36.5-40.5,40.5-44.5,44.5-48.5,48.5-52.5\] and then...

Solution:- Let us consider assumed mean, A = \[92.5\] and h = \[5\] Draw  the table of the given data and append other columns after calculations. Mean,...

Solution:- Draw the table of the given data and append other columns after calculations.

Solution:- Draw the table of the given data and append other columns after calculations.

Solution:- Let us consider the assumed mean A = \[64\]. Here h = \[1\] Mean, \[\bar{X}=A+\frac{\sum\limits_{i=1}^{a}{{{f}_{i}}{{y}_{i}}}}{N}\times h\] Where A = \[64\], h = \[1\]...

  Solution:- Draw  the table of the given data and append other columns after calculations.

Solution:- Draw  the table of the given data and append other columns after calculations.

Solution:- Let us take \[10\] multiples of  \[3\] are  \[3,6,9,12,15,18,21,24,27,30\] We know that Mean = \[\bar{X}=\sum\limits_{i=1}^{a}{{{x}_{i}}}\]...

Solution:- As Mean = Sum of all observations/Number of observations ∴Mean, \[\bar{X}=((n(n+1))2)/n\] = \[(n+1)/2\] and also for Variance, \[{{\sigma...

Solution:- Given \[6,7,10,12,13,4,8,12\] Mean = \[\bar{X}\]= \[\frac{1}{n}\sum\limits_{i=1}^{a}{{{x}_{i}}}\](n=number of observation) \[\sum\limits_{i=1}^{a}{{{x}_{i}}}\]= sum of total observation...

Solution:- The given data is converted into continuous frequency distribution by subtracting \[0.5\] from the lower limit and adding the \[0.5\] to the upper limit of each class intervals and append...

Solution:- Draw  the table of the given data and append other columns after calculations. The class interval containing \[{{N}^{th}}/2\]or \[25\] item is \[20-30\] So, \[20-30\]is the median class....

Solution:- Draw a table of the given data and append other columns after calculations. The sum of calculated data, N= \[\sum\limits_{i=1}^{6}{{{f}_{i}}=100}\],...

Solution:- Draw a table of the given data and append other columns after calculations. The sum of calculated data, N= \[\sum\limits_{i=1}^{8}{{{f}_{i}}=50}\],...

Solution:- Draw a table of the given data and append other columns after calculations. Now, N = 29, which is odd. The cumulative frequency greater than \[14.5\] is \[21\], for which the...

Solution:- Draw a table of the given data and append other columns after calculations. We know that, N = \[26\], which is even. So, median is the mean of the \[13\]and \[14\] observations. Both of...

Solution:- Draw a table of the given data and append other columns after calculations. The sum of calculated data, N = \[\sum\limits_{i=1}^{5}{{{f}_{i}}}=80\],...

  \[{{x}_{i}}\] \[5\] \[10\] \[15\] \[20\] \[25\] \[{{f}_{i}}\] \[7\] \[4\] \[6\] \[3\] \[5\] Solution:- We have to make the table of the given data and append other columns after calculations....

Solution:- To find the median arrange the given observations in ascending order, \[36,42,45,46,46,49,51,53,60,72\] Total number of observations = \[10\] Then, Median = (\[{{(10/2)}^{th}}\]...

Solution:- To find the median arrange the given observations in ascending order, \[10,11,11,12,13,13,14,16,16,17,17,18\] Total number of observations = \[12\] Then, Median = (\[{{(12/2)}^{th}}\]...

Solution:- To find mean deviation, first we have to find mean\[(\overline{x})\] \[\overline{x}=\frac{1}{10}\sum\limits_{i=1}^{10}{{{x}_{i}}}=\frac{500}{10}=50\] Determine the respective values of...

Solution:- Given data \[4\], \[7\], \[8\], \[9\], \[10\], \[12\], \[13\], \[17\] To find mean deviation,  first we have to find mean\[(\overline{x})\]...