Answer: According to the question, the length is: l = 20 cm =0.2 m and the frequency is, v = 1237.5 Hz We know that the velocity of sound in air = 330 m/s The following expression is: l = λ/4 λ = 4l...
Answer: According to the question, the length is, l = 12 m and the total mass, M = 2.10 kg Mass per unit length is given by7 m = M/l = 2.1/12 and we know that tension si: T = 2.06 × 104 N Therefore,...
![K_{c}=\frac{\left[N H_{3}{ }^{4}\left[\mathrm{O}_{2}\right]^{5}\right.}{[\mathrm{NO}]^{4}\left[\mathrm{H}_{2} \mathrm{O}\right]^{6}}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-951fdaf6f5740b9392c024eddb4c57da_l3.png "Rendered by QuickLaTeX.com")
Write the balanced chemical equation corresponding to this expression.Answer: The equilibrium constant, Kc, is defined as the product of the equilibrium concentrations of products over the equilibrium concentrations of reactants, each raised to the power of the...
mol of 
mol of 
and 
of 
is introduced into a 
reaction vessel at 
. At this temperature, the equilibrium constant, 
for the reaction 
is 
Is the reaction mixture at equilibrium? If not, what is the direction of the net reaction?Answer: The given reaction is: $\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})$ The given concentration of various species is...
is placed in a flask at a pressure of 
. At equilibrium, the partial pressure of 
is 
.What is 
for the given equilibrium? 
Answer: The initial concentration of $HI$ is $0.2 atm$. It has a partial pressure of $0.04 atm$ when it is in equilibrium with the surrounding environment. The pressure of $HI$ drops by...
at 
Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is , for the reverse reaction?Answer: Kp and Kc are equilibrium constants for reversible reactions. The equilibrium constant Kp is stated in terms of atmospheric pressure, whereas Kc is expressed in terms of concentrations...
for each of the following reactions: (i) 
(ii) 
Answer: The equilibrium constant, Kc, is defined as the product of the equilibrium concentrations of products over the equilibrium concentrations of reactants, each raised to the power of the...
Given lines are \[\begin{array}{*{35}{l}} 2x\text{ }+\text{ }y\text{ }=\text{ }5\text{ }\ldots \ldots 1 \\ x\text{ }+\text{ }3y\text{ }=\text{ }-8\text{ }\ldots \ldots 2 \\ \end{array}\] Firstly,...
Answer: Beats are created when two waves of nearly identical frequency arrive at the same location at the same time. It is given that the two frequencies are almost equal, that is v1 = v2. And for...
Answer: Speed of sound in air is $ v=\sqrt{\frac{\gamma RT}{M}} $ where 'T' represents the absolute temperature. since both γ and M are constant, we can write: $ \therefore v\alpha \sqrt{T} $ $...
Answer: The wire is stretched both from the end so the frequency of stretched wire is as follows: $ v=\frac{n}{2L}\sqrt{\frac{T}{m}} $ As the number of harmonic n, length L, and tension (T) are kept...
Answer: According to the question, y = 3 sin ωt + 4 cos ωt Let’s suppose that 3 = a cos φ and 4 = a sin φ Then, the equation becomes: y = a cos φ ωt + a sin φ ωt y = a sin (ωt + φ) tan φ = 4/3 φ =...
Answer: Because the medium, frequency, and number of harmonics are the same in open and closed pipes, the number of nodes and (wave) will be the same in both circumstances. When the harmonic is...
Answer: When a sonometer vibrates, the length of the wire is doubled. The sonometer will resonate at 2L if the tuning fork resonates at L. The frequency of the sonometer is expressed using the...
Answer: When the tuning fork B is loaded with wax, the tuning fork's frequency falls below its original frequency. Let's say that when the tuning fork is marked 512 Hz, the tuning fork B is marked...
a) every particle has a fixed amplitude which is different from the amplitude of its nearest particle b) all the particles cross their mean position at the same time c) all the particles are...
a) the frequency of sound as heard by an observer standing on the platform is 400 Hz b) the speed of sound for the observer standing on the platform is 350 m/s c) the frequency of sound as heard by...
a) same frequency b) same phase c) same energy d) different amplitude Answer: The correct answers are a) same frequency b) same phase d) different amplitude Explanation: This is the standing wave...
a) all the particles are vibrating in the same phase b) amplitude of all the particles is equal c) particles of the medium executes SHM d) wave velocity depends upon the nature of the medium Answer:...
a) directly on the density of the medium b) square of bulk modulus of the medium c) inversely on the square root of density d) directly on the square root of bulk modulus of the medium Answer: The...
a) it represents a progressive wave of frequency 60 Hz b) it represents a stationary wave of frequency 60 Hz c) it is the result of the superposition of two waves of wavelength 3 m, frequency 60 Hz...
a) the wave is travelling from right to left b) the speed of the wave is 20 m/s c) frequency of the wave is 5.7 Hz d) the least distance between two successive crests in the wave is 2.5 cm Answer:...
Answer: The correct option is c) Explanation: Apparent Frequency can be expressed in a variety of ways. Assume that the observer (O) and the source (S) are both traveling in the same direction down...
a) one second b) 0.5 second c) 2 seconds d) data given is insufficient Answer: The correct option is b) 0.5 second Explanation: According to the question, m=2.50 kg, l = 20 m and T=200N $ \mu...
a) y = 0.6 sin 2π(t+x/2) b) y = -0.4 sin 2π(t+x/2) c) y = 0.4 sin 2π(t+x/2) d) y = -0.4 sin 2π(t-x/2) Answer: The correct option is b) y = -0.4 sin 2π(t+x/2) Explanation: The amplitude of the...
a) density remains constant b) Boyle’s law is obeyed c) bulk modulus of air oscillates d) there is no transfer of heat Answer: The correct option is d) there is no transfer of heat Explanation:...
a) mechanical transverse waves can propagate through all mediums b) longitudinal waves can propagate through solids only c) mechanical transverse waves can propagate through solids only d)...
a) matter b) energy c) energy and matter d) energy, matter, and momentum Answer: The correct option is b) energy The transfer of energy across a medium is caused by longitudinal waves propagating...
a) frequency of sound waves b) amplitude of sound waves c) wavelength of sound waves d) loudness of sound waves Answer: The correct option is c) wavelength of sound waves Explanation: The velocity...
a) is independent of temperature b) increases with pressure c) increases with an increase in humidity d) decreases with an increase in humidity Answer: The correct option is c) increases with an...
a) λ b) λ/2 c) 2 λ d) 4 λ Answer: The correct answer is c) 2 λ Explanation: According to the question, the wavelength of sound waves in the first medium, λ = u/v ...
a) neither longitudinal nor transverse b) both longitudinal and transverse c) only longitudinal d) only transverse Answer: The correct option is b) both longitudinal and transverse Let's...
Answer: At t = t1 and θ= θ0/a We have, T = 1 sec θ0/2 = θ0 cos 2π/T t1 d θ/dt = – θ0 2π sin 2πt At t = 1/6, that is when θ = θ0/2 d θ/dt = – θ0π√3 v/l = – θ0π√3 v = -θ0π√3l θ0l [1/2 – π√6H/g] gives...
Answer: Let g’ be the acceleration due to gravity of the earth inside the earth g’ = g(1-d/R) R-d = y g’ = g y/R F = -mg y/R F is proportional to (-y) The motion is SHM when the body is in a tunnel....
Answer: Let h0 be the initial height of the columns and dx represent the element that needs to be considered Then the mass is given by: dm = A.dx.ρ Potential energy on the left of dm = (dm)gh Total...
Answer: Let us consider that the verticle displacement at the equilibrium position is $ {{x}_{0}} $ At equilibrium mg = Buoyant Force = $ A{{x}_{0}}\rho g $ When it is displaced further by a...
a) what is the amplitude of oscillation? b) find the frequency of oscillation? Answer: The mass m will oscillate between the lowest and the highest point, which is where it was held in hand. As a...
a) will there be any change in weight of the body, during the oscillation? b) if the answer to part a) is yes, what will be the maximum and minimum reading in the machine and at which position?...
Answer: We can write the following set of equations: θ1 = θ0 sin (wt + δ1) ...............................(1) θ2 = θ0 sin (wt + δ2) ...
Answer: $ \omega =\sqrt{\frac{k}{m}}=5 $ Therefore, $ x=5\sin 5t $
Answer: According to the question, we have: U =U0 (1−cosαx) We know taht, F = −dU / dx $ F=-\frac{d}{dx}\left[ {{U}_{0}}(1-\cos \alpha x) \right] $ $ F=-{{U}_{0}}\alpha \sin \alpha x $ As it is...
Answer: we know that the mean position of the oscillator at x with PE is = 1/2 kx2 Therefore, PE = -m2x2 When PE is maximum, KE = 0 at x = A We get, E = 1/2 mω2A2 PE = 1/2 total energy x2 = 1/2 A2 x...
Answer: A function that represents SHM is written as sin (2π/T t + ϕ) We have, y = sin ωt – cos ωt y = √2 sin (ωt – π/4) The standard equation of SHM has: y = a sin (2π/T t + ϕ) Therefore, T =...
Answer: y represents the distance across which the mass is pulled. The spring's total extension is y + y = 2y. The initial mean location of equilibrium = x0 In the spring, the net extension is equal...
Answer: We know that the expression for the time period of a simple pendulum is T = 2π√l/g Where l represents the length of the pendulum and, g denotes the acceleration due to gravity Therefore,...
Answer:
Answer: We know that the equation for the displacement of SHM is x = a cos ꞷt where velocity can be determined as: v = dx/dt = -aꞷ sin ꞷt Here, the phase displacement is ϕ1 = ꞷt And the phase...
Answer: P' is the perpendicular of the particle Pat's velocity vector at time t. When the particle moves from P to P1, its foot moves from P' to Q, which is away from the positive axis. As a result,...
Answer: According to the question, the distance traveled by the oscillator in one time period = 4A Where A represents the amplitude of the oscillation Therefore, the required ratio becomes = 4A/A =...
Answer: We know that the equation for the displacement of SHM is x = a sin (ꞷt + ϕ) And the velocity of the particle is given by- v = dx/dt = d a sin (ꞷt + ϕ)/dt Expression for the maximum velocity...
Answer: Consider a basic pendulum with a restoring torque and O as the fixed point. The restoring force is given as F = -mg sin θ θ is so small that θ = arc/radius = x/l As a result, F = – mg x/l As...
Answer: The two primary properties of a SHM are as follows: a) Acceleration and displacement are proportionate in magnitude. b) The acceleration is in the direction of the mean position, while the...
Answer: When mass m is pushed from equilibrium by a distance x to the right, spring B is squeezed by a distance x, and the force (kx) is applied to mass m to the left. However, spring A will stretch...
i) velocity of the oscillator is zero ii) speed of the oscillator is maximum Answer: (i) The oscillator's velocity is zero when the points A, C, E, and G are at their extreme positions. (ii) The...
a) average total energy per cycle is equal to its maximum kinetic energy b) average kinetic energy per cycle is equal to half of its maximum kinetic energy c) mean velocity over a complete cycle is...
a) the sign of velocity, acceleration, and force on the particle when it is 3 cm away from A going towards B are positive b) the sign of velocity of the particle at C going towards O is negative c)...
a) average total energy per cycle is equal to its maximum kinetic energy b) average kinetic energy per cycle is equal to half of its maximum kinetic energy c) mean velocity over a complete cycle is...
a) the force is zero at t = 3T/4 b) the acceleration is maximum at t = 4T/4 c) the velocity is maximum at t = T/4 d) the PE is equal to KE of oscillation t = T/2 Answer: The correct options are a)...
a) force acting is directly proportional to the displacement from the mean position and opposite to it b) motion is periodic c) acceleration of the oscillator is constant d) the velocity is periodic...
a) phase of the oscillator is same at t = 0 s and t = 2 s b) phase of the oscillator is the same at t = 2 s and t = 6 s c) phase of the oscillator is the same at t = 1 s and t = 7 s d) phase of the...
a) simple harmonic motion b) non-periodic motion c) periodic motion d) periodic but not SHM Answer: The correct options are a) simple harmonic motion b) non-periodic motion Explanation: Allow the...
a) periodic motion b) simple harmonic motion c) periodic but not simple harmonic motion d) non-periodic motion Answer: The correct answers are a) periodic motion c) periodic but not simple harmonic...
a) v1 + v2 b) c) d) Answer: The correct option is b) Explanation: The spring constants for both the springs have been used in the expressions below: $ {{v}_{1}}=\frac{1}{2\pi...
a) πs b) π/2 s c) 2 πs d) π/t s Answer: The correct option is a) πs Explanation: It isgiven that the maximum velocity is $ {{v}_{\max }}=A\omega =30cm/s $ And the maximum acceleration is as follows:...
a) x(t) = B sin (2πt/30) b) x(t) = B cos (πt/15) c) x(t) = B sin (πt/15 + π/2) d) x(t) = B cos (πt/15 + π/2) Answer: The correct option is a) x(t) = B sin (2πt/30) Explanation: We have, $ x(t)=A\sin...
Answer: “A chemical bond is an attractive force that binds chemical elements together.” Many theories exist for forming chemical bonds, including valence shell electron pair repulsion, electronic,...
a) D will vibrate with maximum amplitude b) C will vibrate with maximum amplitude c) B will vibrate with maximum amplitude d) all four will oscillate with equal amplitude Answer: The correct option...
a) the motion is oscillatory but not SHM b) the motion is SHM with amplitude a + b c) the motion is SHM with amplitude a2 + b2 d) the motion is SHM with amplitude √a2 + b2 Answer: The correct option...
a) an ellipse b) a parabola c) a circle d) a straight line Answer: The correct option is c) a circle Given x=acosωt (i) y=asinωt ...
a) periodic but not simple harmonic b) non-periodic c) simple harmonic and time period is independent of the density of the liquid d) simple harmonic and time period is directly proportional to the...
a) ax = +2x b) ax = +2x2 c) ax = -2x2 d) ax = -2x Which one of the particles is executing simple harmonic motion? Answer: The correct option is d) ax = -2x Explanation: The acceleration in simple...
Given, A = {x: x ∈ W, x < 2}, B = {x : x ∈N, 1 < x < 5} C = {3, 5}; W is the set of whole numbers A = {x: x ∈ W, x < 2} = {0, 1} B = {x : x ∈N, 1 < x < 5} = {2, 3, 4} (i) (B∩C) =...
Given, A = {–1, 2, 3} and B = {1, 3} (i) B × B {1, 3} ×{1, 3} So, B × B = {(1, 1), (1, 3), (3, 1), (3, 3)} As a result, the Cartesian product is {(1, 1), (1, 3), (3, 1), (3, 3)} (ii) A × A {–1, 2,...
a) non-periodic b) periodic but not simple harmonic c) simple harmonic with period 2π/ω d) simple harmonic with period π/ω Answer: The correct option is c) simple harmonic with period 2π/ω The...
a) simple harmonic with period 2p/w b) simple harmonic with period π/ω c) periodic but not simple harmonic d) non-periodic Answer: The correct option is b) simple harmonic with period π/ω...
, where m is the mass of the gas molecule. Answer: Let ρm represent the number of molecules per unit volume Then the expression for the change in momentum by a molecule on front side is = 2m (v +...
(i) A ⊂ {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10} B ⊂ {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10} C ⊂ {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10} As a result, the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10} is the universal set...
Answer: Volume of the box = 1 m3 = V1 Initial pressure P1 = 1.5 atm Final pressure P2 = 1.4 atm Air pressure Pa = 1 atm Initial temperature T1 = 300 K Final temperature T2 = 300 K Area of the hole =...
Answer: We know that, Time = distance/speed Number of particles per unit volume v = N/volume n = 0.0167 km-3 d = 10 × 10-3 km v = 150 km/hr Therefore, we get: time = 225 hrs
(i) Because odd numbers are not divisible by two, a set of odd natural numbers divisible by two is a null set. (ii) Because 2 is an even prime number, the set of even prime numbers is not a null...
Speed (m/s) % of molecules 200 10 400 20 600 40 800 20 1000 10 a) calculate Vrms and hence T (m = 3.0 × 10-26 kg) b) if all the molecules with speed 1000 m/s escape from the system, calculate new...
(i) Because there are 12 items in the set of months of a year, it is a finite set. (ii) Because it contains an unlimited amount of natural numbers, 1, 2, 3,... is an infinite set.
Because an infinite number of circles can pass through the origin (0, 0), the set of circles travelling through the origin is endless.
(i) A = {2, 4, 6, 8, 10}; B = {x: x is a positive even integer and x ≤ 10} = {2, 4, 6, 8, 10} So, A = B (ii) A = {x: x is a multiple of 10} B = {10, 15, 20, 25, 30 …} We know that 15 ∈ B but 15 ∉ A....
A = {2, 4, 8, 12}; B = {1, 2, 3, 4}; C = {4, 8, 12, 14} D = {3, 1, 4, 2}; E = {–1, 1}; F = {0, a} G = {1, –1}; H = {0, 1} We know, 8 ∈ A, 8 ∉ B, 8 ∉ D, 8 ∉ E, 8 ∉ F, 8 ∉ G, 8 ∉ H A ≠ B, A ≠ D, A ≠...
a) there is no atmosphere on moon b) there is a fall in temperature with altitude Answer: a) The moon has no atmosphere since the gravitational pull is minimal and the Vrms is bigger on the moon,...
Answer: According to the question, the final KE of the gas is 0 The change in KE is as follows: ∆K= 1/2 (nm)v2 ∆T is the change in the temperature ∆U = nCv∆T ∆K = ∆U Making use of the expression, we...
Answer: According to the question, the volume occupied by the molecules of a gas is 22400 cc and the number of molecules in 1 cc of hydrogen are 2.688 × 1019 We know that the hydrogen has a total...
a) the number of atoms of helium in the balloon b) the total internal energy of the system Answer: We know that the average KE per molecule is 3/2kT No.of moles of helium are n = 5 g mole We have T...
Answer: We have, PV = P(m/ρ) = constant P/ ρ = constant Volume = m/ ρ where m is constant When air is pushed into the cycle's tyre, the mass of the air increases as the number of molecules...
Answer: We know that volume of 1 molecule = 4/3 πr3 = 4.20 × 10-30 m3 And the number of moles in 0.5 g H2 gas = 0.25 mole Volume of H2 molecule in 0.25 mole = 1.04×6.023× 10+23-30 = 6.264 ×...
a) average KE b) rms speeds Answer: a) From the above result, the pressure and temperature are the same, therefore, KEc > KEb > KEa b) When P and T are constant, (Vrms)c > (Vrms)b >...
V1 V2 μ1 μ2 p1 p2 Answer: We know that for an ideal gas, PV = μRT The two equations that we can write are: P1V1 = μ1R1T1 P2V2 = μ2R2T2 P1 = 1 atm, P2 = 2 atm and V1 = 2L, V2 = 3L Also, T1 = T = T2...
Answer: We know that that we can write: I α (1/d2) d1 = 1Å d2 = 2Å Therefore, l1 : l2 = 4 : 1 The ratio of the mean free paths of the molecules is 4:1
Answer: We know that oxygen has 5 degrees of freedom. Therefore, energy per mole = (5/2)RT Therefore, for 2 moles of oxygen, energy = 5RT Neon has 3 degrees of freedom. Therefore, energy per mole...
Answer: Expression for root mean square velocity is as follows: $ {{v}_{rms}}=\sqrt{\frac{v_{1}^{2}+v_{2}^{2}+v_{3}^{2}+......+v_{n}^{2}}{n}} $ For two meolecules, the formula reduces to: $...
Answer: According to the question, Vrms = 100 m/s T1 = 300 K and T2 = 400 K Expression for root mean square velocity is Vrms = √3RT/M Upon substituting the given values, we get Vrms = 115.4...
Answer: According to the question, T1 = 27oC = 300 K and the volume V1 = 100 cm3 It is known that V is proportional to T So, we can write V/T = constant Or, V1/T1 = V2/T2 Upon re-arranging, we have...
Answer: According to the question, the molar mass = mass of Avagadro's number of atoms = 6.023 × 1023 atoms Mass of gold is m = 39.4 g and the molar mass of gold is M = 197 g/mol We know that 197 g...
Solution: Hence, \[\begin{array}{*{35}{l}} 1\text{ }\le \text{ }y\text{ }<\text{ }2 \\ \Rightarrow ~1\text{ }\le \text{ }\left| x-\text{ }\text{ }2 \right|\text{ }<\text{ }2 \\ \end{array}\]...
Let \[z\text{ }=\text{ }x\text{ }+\text{ }iy\] Given that, \[arg\text{ }\left( z-\text{ }\text{ }1 \right)\text{ }=\text{ }arg\text{ }\left( z\text{ }+\text{ }3i \right)\] \[\Rightarrow ~arg\text{...
Let z = x + iy Now, \[\Rightarrow ~{{x}^{2}}~+\text{ }x\text{ }\text{ }-2\text{ }+\text{ }{{y}^{2}}~=\text{ }4\text{ }\left( {{x}^{2}}~\text{ }-2x\text{ }+\text{ }1\text{ }+\text{ }{{y}^{2}}...
SOLUTION: a = cos θ + i sin θ
a) because of collisions with moving parts of the wall only b) because of collisions with the entire wall c) because the molecules gets accelerated in their motion inside the volume d) because of...
As indicated by the inquiry, \[P\left( n \right)\text{ }is\text{ }2\text{ }+\text{ }4\text{ }+\text{ }6\text{ }+\text{ }\ldots \text{ }+\text{ }2n\text{ }=\text{ }n^2\text{ }+\text{...
Answer: The correct answer is a) c)
The 4d, 3d, 4p, 3d, 3p, and 4p orbitals are home to electrons 1, 2, 3, 4, 5, and 6. (respectively). Ranking these orbitals in the increasing order of energies: (3p) < (3d) < (4p) < (4d).
As indicated by the inquiry, \[P\left( n \right)\text{ }is\text{ }2n\text{ }<\text{ }\left( n\text{ }+\text{ }2 \right)!\] In this way, subbing various qualities for n, we get, \[P\left( 0...
The net positive charge acting on an electron in an atom's orbital with more than one electron is known as the nuclear charge. The nuclear charge increases as the atomic number increases. Silicon...
a) obeys Maxwell’s distribution b) have the same value for all molecules c) equals the translational kinetic energy for each molecule d) is 2/3rd the translational kinetic energy for each molecule...
a) the total energy per unit volume d) only the translational part of energy because rotational energy is very small compared to the translational energy c) only the translational part of the energy...
As per the inquiry, \[P\left( n \right)\text{ }=\text{ }n\left( n^2\text{ }+\text{ }5 \right)\] is distinguishable by 6. Along these lines, subbing various qualities for n, we get, \[P\left( 0...
As indicated by the inquiry, \[P\left( n \right)\text{ }=\text{ }n^3\text{ }-\text{ }n\] is distinct by 6. Along these lines, subbing various qualities for n, we get, \[P\left( 0 \right)\text{...
a) will be valid b) will not be valid since the ions would experience forces other than due to collision with the walls c) will not be valid since collisions with walls would not be elastic d) will...
a) 1.1 p b) p c) less than p d) between p and 1.1 Answer: The correct option is d) between p and 1.1 Explanation:
As indicated by the inquiry, \[P\left( n \right)\text{ }=\text{ }xn\text{ }\text{ }yn\] is detachable by \[x\text{ }\text{ }y,\text{ }x\] whole numbers with\[x\text{ }\ne \text{ }y\] . In this way,...
As indicated by the inquiry, \[~P\left( n \right)\text{ }=\text{ }7n\text{ }\text{ }2n\] is distinct by 5. In this way, subbing various qualities for n, we get, \[~P\left( 0 \right)\text{ }=\text{...
a) f1(v) + f2(v) = f(v) obeys the Maxwell’s distribution law b) f1(v), f2(v) will obey the Maxwell’s distribution law separately c) neither f1(v) nor f2(v) will obey the Maxwell’s distribution law...
The major gases that cause greenhouse effect are: 1) Chlorofluorocarbons (CFCs) 2) Methane (CH4) 3) Carbon dioxide (CO2) 4) Nitrous oxide (NO) 5) Water(H2O) 6) Ozone (O3)
a) same as the pressure initially b) 2 times the pressure initially c) 10 times the pressure initially d) 20 times the pressure initially Answer: The correct option is d) 20 times the pressure...
Carbon dioxide (CO2) and carbon monoxide (CO) are both produced when various fuels are burned. In nature, carbon monoxide is harmful, but carbon dioxide is non-toxic. Because carbon monoxide forms a...
a) P1 > P2 b) P1 = P2 c) P1 < P2 d) data is insufficient Answer: The correct option is a) P1 > P2 Explanation: When the pressure of an ideal gas is constant, Chale's law is obeyed, i.e. V ∝...
a) both p and V of the gas will change b) only p will increase according to Charle’s law c) V will change but not p d) p will change but not V Answer: The correct option is c) V will change but not...
Solution: (i) The statement is true As per the question, $35 \in\{x \mid x$ has exactly four positive factors $\}$ 1, 5, 7, 35 are the possible positive factors of 35 So, 35 belongs to provided set...
a) adiabatic process b) isothermal process c) isobaric process d) isochoric process Answer: The correct option is b) isothermal process Explanation: In an isothermal process, when the temperature...
a) the pressure on EFGH would be zero b) the pressure on all the faces will the equal c) the pressure of EFGH would be double the pressure on ABCD d) the pressure on EFGH would be half that on ABCD...
Solution: As per the question, $Y=\left\{x \mid x\right.$ is a positive factor of the number $2^{p-1}\left(2^{p}-1\right)$, in which $2^{p}-1$ is a prime number $\}$. Roster form, 1 and p itself are...
a) remains the same because 500 m/s is very much smaller than vrms of the gas b) remains the same because the motion of the vessel as a whole does not affect the relative motion of the gas molecules...
Frequency of the light wave $\nu$ = $\frac{1}{Period} \frac{1}{Period}$ $=\frac{1}{2.0\times 10^{-10}\, s} =5.0\times 10^{9}\, s^{-1 }$ Wavelength of the light wave$\lambda=c\nu$ Where, c denotes...
As per the inquiry, \[P\left( n \right)\text{ }=\text{ }4n\text{ }\text{ }1\] is separable by 3. Thus, subbing various qualities for n, we get, \[P\left( 0 \right)\text{ }=\text{ }40\text{...
\({}_{6}^{13}C\): Mass number of carbon-13 = 13 Atomic number of carbon = Number of protons in one carbon atom = 6 Therfore, total number of neutrons in 1 carbon atom = Mass number – Atomic number =...
As indicated by the inquiry, P(n) which is valid for all n. Let P(n) be, ⇒ P(k) is valid for all k. In this manner, P(n) is valid for all n.
1 electron weighs 9.109*10-31 kg. Therefore, number of electrons that weigh 1 g (10-3 kg) = 1.098*1027 electrons (ii) Mass of one mole of electrons = NA* mass of one electron =...
c) using the first law of thermodynamics, write down the relation between Q, Pa, V, V0, and k. Answer: c) The relation between Q, Pa, V, V0, and k is as follows: dQ = dU + dW where, dU = Cv (T – T0)...
a) what is the initial pressure of the system? b) what is the final pressure of the system? Answer: a) Pa is the initial pressure of the system inside the cylinder b) The final pressure of the...
Answer: The slope of the graph as given by: $ \left( {{V}_{0}},{{P}_{0}} \right)={{\left( \frac{dP}{dV} \right)}_{{{V}_{0}},{{P}_{0}}}} $ Making use of the above relation, we can determine that $...
AB: constant volume BC: constant pressure CD: adiabatic DA: constant pressure Answer: a) AB: constant volume b) BC: constant pressure c) CD: adiabatic QCD = 0 d) DA: constant pressure, there is...
A to B: volume constant B to C: adiabatic C to D: volume constant D to A: adiabatic VC = VD = 2VA = 2VB c) what is the work done by the engine in one cycle in terms of PA, PB, VA? d) what is the...
A to B: volume constant B to C: adiabatic C to D: volume constant D to A: adiabatic VC = VD = 2VA = 2VB a) in which part of the cycle heat is supplied to the engine from outside? b) in which part of...
c) given the internal energy for one mole of gas at temperature T is (3/2)RT, find the heat supplied to the gas when it is taken from state 1 to 2 with V2 = 2V1. Answer: We know that the expression...
a) find the work done when the gas is taken from state 1 to state 2 b) what is the ratio of temperature T1/T2 if V2 = 2V1 Answer: According to the question, PV1/2 = K = constant a) Expression for...
(i) 28.7 pm $1 pm = 10^{ -12 } \; m$ $28.7 pm = 28.7 \times 10^{ -12 } \; m$ $= 2.87 \times 10^{ -11 } \; m$ (ii) 15.15 pm $1 pm = 10^{ -12 } \; m$ $15.15 pm = 15.15 \times 10^{ -12 } \; m$...
(i) Empirical formula 1 mole of $CO_{ 2 }$ contains 12 g of carbon Therefore, 3.38 g of $CO_{ 2 }$ will contain carbon = $\frac{ 12 \; g }{ 44 \; g } \; \times 3.38 \; g$ = 0.9217 g 18 g of...
If a person is not wearing a seat belt and abruptly hits the brakes, he will fall forward and bang his head against the steering wheel because his upper body will continue to move in the same...
Mass of body, m = 2 kg Time, t = 0 Initial velocity, v1 = 0 From graph, we know that t ≥ 0 to t ≤ 4 which is a straight line. The velocity of the body is constant v2 = tan θ = 3/4 = 0.75 m/s At t ≥...
When the lift lowers with an acceleration a, the apparent weight on the weighing scale decreases. W' denotes the apparent weight. Therefore, W' = R = (mg – ma) = m(g – a) As a result, W' = 50(10-9)...
Given, m1 = 50 kg m2 = 0.5 kg u1 = 5 m/s u2 = 5 m/s v1 = ? v2 = 15 m/s The law of conservation of momentum states that Final momentum equals initial momentum. u1 = m1v1 + m2v2 (m1 + m2) We obtain by...
The correct answer is: c) the impulse imparted to each ball is 0.5 Ns d) the impulse and the force on each ball are equal in magnitude and opposite in direction
c) for A to move up the plane, θ2 must always be greater than θ1 d) B will always slide down with constant speedThe correct answer is: b) A will just start moving up the plane when \(\mu =\frac{\sin {{\theta }_{2}}-\sin {{\theta }_{1}}}{\cos {{\theta }_{1}}}\) c) for A to move up the plane, θ2 must always be...
The correct answer is: b) if m2 > m1(sin θ + μ cos θ), the body will move up the plane d) if m2 < m1 (sin θ – μ cos θ), the body will move down the plane
The correct answer is: a) the bodies will move together if F = 0.25 mg b) the body A will slip with respect to B if F = 0.5 mg d) the bodies will be at rest if F = 0.1 mg e) the maximum value of F...
The correct answer is: a) the force at t = (1/8) sec on the particle is -16π2Am b) the particle is acted upon by on impulse of magnitude 4π2Am at t = 0 sec and t = (1/4) sec d) the particle is not...
The correct answer is b) mv/2 eastward and is due to the friction on the tyres exerted by the road
The correct answer is b) 10 s
The correct answer is a) 136 N
The correct answer is d) both Newton’s second and third law
The correct option is c) 1.5 kg.m/s
The correct answer is (c) -(0.9i+1.2j)
The correct answer is b) the force acting on the scale is zero and the torque acting about the centre of mass of the scale is also zero
The correct option is c) all parts of the ball have the same velocity and the velocity is constant
The net buoyant force Equals vpg when the dragging viscous force of the air on the balloon is ignored. Where v is the volume of air that has been displaced. The upward net density is denoted by p....
Y = stress/strain Y = FL/A∆L WD = F∆L KE = 5 × 10-4 J WD = KE ∆L = 5 × 10-7 m
Solution: Radius of perigee is given as $r_{p}=2R$ Radius of apogee is given as $r_{a}=6R$ And we know, $r_{p}=a(1-e)=2R$ and, $r_{a}=a(1+e)=6R$ From the above equations, we get $e = 1/2$ From the...
M is the rocket's mass at any given moment t. The rocket's velocity is v. The mass of the gas expelled during the time interval t is m. As a result, K = 1/2 u2∆m
a) For ball 1 the total mechanical energy is conserved b) Ball 1 reaches D c) Ball 3 reaches back A
a) Work against gravity equals mgh 5 m= h 50 J WD against gravity b) The work done against the friction force is fs = 53 J. d) WD against gravity = 50 J increase in PE d) The system's increase in KE...
car engine Efficiency = 0.5 Energy given by the car with 1 litre of petrol = 1.5 × 107 WD = 1.5 × 107 f = 103 N
The energy used up is given as = mgh mg = 600 N h = 0.25m No.of steps in 6 km = 6000 steps Energy used in 6000 m = (6000)(600)(0.25)J Energy utilized in jogging = 9 × 104 J
KE = 1/2 mv2 m = 50000 kg v = 10 m/s KE = 2500000J KE of spring = 10% of the KE wagon K = 5 × 105 N/m
Energy transferred by the rain to the surface of the earth = 1/2 mv2 The velocity of the rain = 9 m/s Mass = (volume)(density) = 1000 kg Energy transferred by 100 cm rainfall = 1/2 mv2 =...
a) PE at the highest point = 10 J b) Gain in KE = 1/2 mv2 = 1.250 J c) Gain in KE is not equal to the PE
a) After the impact, bob A does not rise much because the PE of bob A is converted to KE and the momentum is transferred to bob B. (B) The speed of bob B is calculated as the sum of bob A's KE and...
a) Mass of the earth is given as $M=6\times 10^{24}kg$ Radius of the earth is given as $R=6.4 \times 10^{3}m$ Time period is given as $24.36 \times 10^{2}s$ $G=6.67 \times 10^{-11}Nm^{2}kg^{-1}$...
E = V + K and V > E for area A, implying that the KE is negative and therefore this is not feasible. K = E – V and V E for area B, implying that both energies are larger than zero. V = E – K and...
a) Let v1 and v2 be the velocities of the two balls after the collision. According to the law of conservation of momentum, mv0 = mv1 + mv2 v2 = v1 + 2ev0 e < 1 b) Using the law of conservation of...
From the given graph of KE versus x From the below graph of velocity versus x
a) When the string is severed at point B, the particle's tangential velocity will be vertically downward, and the bob will travel in the same direction. b) When the string is severed at point C, the...
KE1 = KE2 WD1 = WD2 F1s1 = F2s2 F1 = F2 s1 = s2
The kinetic energy of work done in a circular motion remains unchanged.
P = WD/time WD is one beat of heart = 0.5 J WD in 72 beats = 36 J P = WD/t = 0.6 W
P = WD/time = Fs cos θ/t = mgh cos θ/t h = 10 m t = 20 sec F = mg = 1000 Therefore, P = 500 Watts
Because there is no non-conservative force, the kinetic energy and total linear momentum of the billiard balls are preserved.
When the conservative force acts on the body during motion, the work done by the moving body is zero. When a non-conservative force acts on a moving body, the work done by the body is not zero.
The free-falling body's total mechanical energy is not preserved since it is utilised to overcome the frictional force of the air molecules.
WD = Fs cos θ WD = Fs cos 90o = 0 Hence, the work done by the car against the gravity is zero.
a) The applied force produces positive work. b) The gravitational pull produces negative work.
In the event of an elevator falling, the number of passengers is limited because it is not a free fall and descends at a constant speed.
The block is clearly tilted on the plane in the illustration above. There is no work done since there is no displacement and no waste of energy.
c) if spring is massless, the final state of the M1 is a state of rest d) if the surface on which blocks are moving has friction, then a collision cannot be elastic
b) the velocity of the bullet will be more than half of its earlier velocity d) the bullet will move in a different parabolic path f) the internal energy of the particles of the target will...
b) work done by all the force on man is zero d) the reaction force from a step does not do work because the point of application of the force does not move while the force exists
N d) 
Nc) 1.05 × 104 N
(b
Potential Energy of the body on the earth is given by $-GMm/R$ When the body is closer to the equator, then PE becomes $-GMm/2R$ Gain in PE is $1/2 mgR$
Total energy of the satellite is $-GMm/2R$
M = mass of the spheres R = radius of the spheres. P = midpoint of A and B. The magnitude of the force is expressed as, $F_{1}=F_{2}=\frac{GMm}{5R^{2}}$ As the resultant force exerted on the object...
a) The equatorial plane and the orbital plane of a polar satellite form a $90^{o}$ angle. b) A geostationary satellite's equatorial plane and orbital plane are at an angle of $0^{o}$.
No. As gravitation is independent of the medium, a body can be shielded from the gravitational pull of adjacent matter.