c) using the first law of thermodynamics, write down the relation between Q, Pa, V, V0, and k. Answer: c) The relation between Q, Pa, V, V0, and k is as follows: dQ = dU + dW where, dU = Cv (T – T0)...

a) what is the initial pressure of the system? b) what is the final pressure of the system? Answer: a) Pa  is the initial pressure of the system inside the cylinder b) The final pressure of the...

 Answer: The slope of the graph as given by: $ \left( {{V}_{0}},{{P}_{0}} \right)={{\left( \frac{dP}{dV} \right)}_{{{V}_{0}},{{P}_{0}}}} $ Making use of the above relation, we can determine that $...

AB: constant volume BC: constant pressure CD: adiabatic DA: constant pressure Answer: a) AB: constant volume b) BC: constant pressure c) CD: adiabatic QCD = 0 d) DA: constant pressure, there is...

A to B: volume constant B to C: adiabatic C to D: volume constant D to A: adiabatic VC = VD = 2VA = 2VB c) what is the work done by the engine in one cycle in terms of PA, PB, VA? d) what is the...

A to B: volume constant B to C: adiabatic C to D: volume constant D to A: adiabatic VC = VD = 2VA = 2VB a) in which part of the cycle heat is supplied to the engine from outside? b) in which part of...

c) given the internal energy for one mole of gas at temperature T is (3/2)RT, find the heat supplied to the gas when it is taken from state 1 to 2 with V2 = 2V1. Answer: We know that the expression...

a) find the work done when the gas is taken from state 1 to state 2 b) what is the ratio of temperature T1/T2 if V2 = 2V1 Answer: According to the question, PV1/2 = K = constant a) Expression for...

a) the expansion takes place at constant temperature b) the expansion takes place at constant pressure Plot the P-V diagram for each case. In which of the two cases, is the work done by the gas...

Answer: To determine the temperature inside the refrigerator, we must first determine the work that has been done. W = 0 Q1 = Q2 β = ∞ Where β represents the coefficient of performance According to...

Answer: Expression for the efficiency of the Carnot engine is as follows; $ \eta =1-\frac{{{T}_{2}}}{{{T}_{1}}} $ Where T1 = 300 K and T2 = 270 K We are given that the efficiency is 50% = 0.5...

Answer: The equation before and after the stroke can be written as follows: $ {{P}_{1}}{{V}_{1}}={{P}_{2}}V_{2}^{\gamma } $ $ P{{\left( V+\Delta V \right)}^{\gamma }}=(P+\Delta P){{V}^{\gamma }} $ $...

Answer: According to the question, the height of the stairs is h = 10 m And the work done to burn 5 kg of fat is W = (5)(7000 × 103)(4.2) W = 147 × 106 J Therefore, the work done towards burning of...

Answer: According to Charle's law, the air pressure in a car tyre increases while the volume remains constant during driving. Temperature and pressure are proportional. As a result, the pressure of...

Yes, it is possible to raise a gas's temperature without adding heat to it. During adiabatic compression, this is feasible. In adiabatic compression, we know that  dQ=0 ∴ Making use of the first law...

Answer: When a refrigerator door is left open, the room becomes hot because the quantity of heat received by the refrigerator, as well as the work performed by the refrigerator, is rejected into the...

Answer: From path 1 we can say that, Q1 = +1000 J and the work done is W1 – W2 = 100 Where W1 represents the work done through path 1 and W2 denotes the work done through path 2. Therefore, we can...

Answer: Yes, if the complete amount of heat provided to the system is used for expansion. To maintain a constant temperature, the system's work against the environment should be compensated by the...

If W > 0, then possibilities are: a) Q1 > Q2 > 0 b) Q2 > Q1 > 0 c) Q2 < Q1 < 0 d) Q1 < 0, Q2 > 0 Answer: The correct options are a) Q1 > Q2 > 0 c) Q2 < Q1 < 0...

1 to 2 is isothermal 2 to 3 is adiabatic 3 to 1 is adiabatic Such a process does not exist because a) heat is completely converted to mechanical energy in such a process, which is not possible b)...

a) change in internal energy is the same in IV and III cases, but not in I and II b) change in internal energy same in all the four cases c) work done is maximum in case I d) work done is minimum in...

a) dU = 0 b) dQ = 0 c) dQ = dU d) dQ = dW Answer: The correct options are a) dU = 0 d) dQ = dW Explanation: Internal energy is a function of temperature. Since temperature is constant...

a) the increase in temperature of an iron rod by hammering it b) a gas in a small container at a temperature T1 is brought in contact with a big reservoir at a higher temperature T2 which increases...

a) b) c) d) Answer: The correct option is b)

Answer: The correct answer is a)  

a) 6P0V0 b) -2P0V0 c) +2P0V0 d) +4P0V0 Answer: The correct option is d) +4P0V0 Explanation Work done by the gas is equal to the area of rectangle ABCDA =AB×BC =(2V0)P0 =2P0V0 This work is done on...

Out of the following diagrams, which represent the T-P diagram? a) iv b) ii c) iii d) i Answer: The correct option is c) iii Explanation: In the above-mentioned graph, PV=constant Moreover, PV=nRT...

a) 0.25 kg b) 2.25 kg c) 0.05 kg d) 0.20 kg Answer: The correct option is a) 0.25 kg Explanation: Energy produces = 14.5 × 103 cal/min. Then the amount of sweat evaporated per min is given...

a) 4 b) 3 c) 2 d) 1 Answer: The correct option is c) 2 Explanation: The adiabatic process occurs when a thermodynamic system changes in such a way that no heat exchange occurs between it and its...